NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    For complete combustion of ethanol, \[{{C}_{2}}{{H}_{5}}OH\left( l \right)+3{{O}_{2}}\left( g \right)\xrightarrow{{}}2C{{O}_{2}}\left( g \right)+3{{H}_{2}}O\left( l \right),\] the amount of heat produced as measured in bomb calorimeter, is \[1364.47\text{ }kJ\text{ }mo{{l}^{-1}}\] at\[25{}^\circ C\]. Assuming ideality the enthalpy of combustion, \[{{\Delta }_{c}}H\], for the reaction will be: \[\left( R=8.314\text{ }kJ\,mo{{l}^{-1}} \right)\]

    A) \[-1366.95\text{ }kJ\text{ }mo{{l}^{-1}}\]

    B) \[-1361.95\text{ }kJ\,mo{{l}^{-1}}\]

    C) \[-1460.95\text{ }kJ\,mo{{l}^{-1}}\]

    D) \[-1350.50\text{ }kJ\,mo{{l}^{-1}}\]

    Correct Answer: A

    Solution :

    [a] \[{{C}_{2}}{{H}_{5}}OH\left( l \right)+3{{O}_{2}}\left( g \right)\xrightarrow{{}}\] \[2C{{O}_{2}}\left( g \right)+3{{H}_{2}}O\left( l \right)\]             Bomb calorimeter gives \[\Delta U\] of the reaction Given, \[\Delta U=-1364.47\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta {{n}_{g}}=-1\] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\] \[=-\,1364.47-\frac{1\times 8.314\times 298}{1000}\] \[=-1366.93\text{ }kJ\text{ }mo{{l}^{-1}}\]


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