A) \[-1366.95\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[-1361.95\text{ }kJ\,mo{{l}^{-1}}\]
C) \[-1460.95\text{ }kJ\,mo{{l}^{-1}}\]
D) \[-1350.50\text{ }kJ\,mo{{l}^{-1}}\]
Correct Answer: A
Solution :
[a] \[{{C}_{2}}{{H}_{5}}OH\left( l \right)+3{{O}_{2}}\left( g \right)\xrightarrow{{}}\] \[2C{{O}_{2}}\left( g \right)+3{{H}_{2}}O\left( l \right)\] Bomb calorimeter gives \[\Delta U\] of the reaction Given, \[\Delta U=-1364.47\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta {{n}_{g}}=-1\] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\] \[=-\,1364.47-\frac{1\times 8.314\times 298}{1000}\] \[=-1366.93\text{ }kJ\text{ }mo{{l}^{-1}}\]You need to login to perform this action.
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