A) \[10\text{ }d{{m}^{3}},1000\text{ }J\]
B) \[8\text{ }d{{m}^{3}},\text{ }-800\text{ }J\]
C) \[10d{{m}^{3}},-800\text{ }J\]
D) \[10d{{m}^{3}},-1000J\]
Correct Answer: C
Solution :
[c] \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[\therefore V=\frac{5bar\times 2d{{m}^{3}}}{1bar}=10d{{m}^{3}}\] Work, \[W=-{{P}_{ext}}({{V}_{final}}-{{V}_{initioal}})\] \[=-1\,bar\text{ }\left( 10-2 \right)\] \[=-1\times {{10}^{5}}Pa\times 8\times {{10}^{-3}}{{m}^{3}}\] \[=-800\text{ }J\]
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