A) Work done by gas is = 5 R
B) Work done over the gas is = 10 R
C) Work done by the gas = 10 R
D) Work done =0
Correct Answer: B
Solution :
[b] For 5 moles of gas at temperature T, \[P{{V}_{1}}=5RT\] For 5 moles of gas at temperature \[T-2\], \[P{{V}_{2}}=5R\left( T-2 \right)\] \[\therefore \text{ }P({{V}_{2}}-{{V}_{1}})=5R\left( T-2-T \right);\] \[P\Delta V=-10R,\] \[-P\Delta V=10R\] When \[\Delta V\] is negative, W is + ve.
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