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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    When the state of a gas adiabatically changed from an equilibrium state A to another equilibrium state B an amount of work done on the system is 35 J. If the gas is taken from state A to B via process in which the net heat absorbed by the system is 12 cal, then the net work done by the system is \[\left( 1\text{ }cal=4.19J \right)\]

    A) 13.2 J

    B) 15.4 J

    C) 12.6 J

    D) 16.8 J

    Correct Answer: B

    Solution :

    [b] In the first-case adiabatic change, \[\Delta Q=0,\Delta W=-35J\] From 1st law of thermodynamics, \[\Delta Q=\Delta U+\Delta W,\] In the second case \[\Delta Q=12cal=12\times 4.2\text{ }J=50.4\text{ }J\] \[\Delta W=\Delta Q-\Delta U=50.4-35=15.4J\]


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