NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    For the auto-ionization of water at \[25{}^\circ C,\] \[{{H}_{2}}O(l)\rightleftharpoons {{H}^{+}}(aq)+O{{H}^{-}}(aq)\]  equilibrium constant is \[{{10}^{-14}}\]. What is \[\Delta G{}^\circ \] for the process?

    A) \[\simeq 8\times {{10}^{4}}J\text{ }mo{{l}^{-1}}\]     

    B) \[\simeq 3.5\times {{10}^{4}}Jmo{{l}^{-1}}\]

    C) \[\simeq 2\times {{10}^{4}}Jmo{{l}^{-1}}\]    

    D) None of these

    Correct Answer: A

    Solution :

    [a] \[\Delta {{G}^{{}^\circ }}=-RT\] ln K \[=-8.314J{{K}^{-1}}\,mo{{l}^{-1}}\times 298K\times 2.303log\text{ }{{10}^{-14}}\] \[=7.98\times {{10}^{4}}\simeq 8\times {{10}^{4}}J\,mo{{l}^{-1}}\]


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