NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    What is the equilibrium constant if ATP hydrolysis by water produce standard free energy of \[-50\text{ }kJ/mol\] under normal body conditions?                

    A) \[2.66\times {{10}^{8}}\]         

    B) \[5.81\times {{10}^{8}}\]

    C) \[1.18\times {{10}^{7}}\]         

    D) \[1.98\times {{10}^{8}}\]

    Correct Answer: A

    Solution :

    [a] \[\Delta G=-RT\] ln \[{{K}_{eq}}\]: Normal body temperature \[=37{}^\circ C\] \[\Rightarrow -50\frac{KJ}{mol}=8.314\frac{J}{Kmol}\times 310\,\ln {{K}_{eq}}\] \[\Rightarrow 19.39=\ln {{K}_{eq}}\] \[\Rightarrow {{K}_{eq}}=2.6\times {{10}^{8}}\]


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