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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    If the co-efficient of performance of a refrigerator is 5 and operates at the room temperature \[\]the temperature inside the refrigerator is

    A) 240 K   

    B)        250 K

    C) 230 K   

    D)        260 K

    Correct Answer: B

    Solution :

    [b] Here, Coefficient of performance \[(\beta )=5\] \[{{T}_{1}}=27{}^\circ \text{C=}\left( 27+273 \right)K=300K\] \[\text{As, }\beta =\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}\Rightarrow 5=\frac{{{T}_{2}}}{300-{{T}_{2}}}\]\[\text{or }1500-5{{T}_{2}}={{T}_{2}}\text{ or }6{{T}_{2}}=1500\] \[\therefore {{T}_{2}}=\frac{1500}{6}=250K\]


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