NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    \[\Delta H_{f}^{0}\] of water is\[-285.8\text{ }kJ\text{ }mo{{l}^{-1}}\]. If enthalpy of neutralisation of monoacidic strong base is \[-57.3\text{ }kJmo{{l}^{-1}}\]. \[\Delta H_{f}^{0}\] of \[O{{H}^{-}}\] ion will be

    A) \[-114.25\text{ }kJ\,mo{{l}^{-1}}\]

    B)   \[114.25\text{ }kJ\text{ }mo{{l}^{-1}}\]

    C) \[228.5\text{ }kJ\,mo{{l}^{-1}}\]          

    D) \[-228.5\text{ }kJ\text{ }mo{{l}^{-1}}\]

    Correct Answer: D

    Solution :

    [d] \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}O(l);\] \[\Delta H=-285.8\text{ }kJ\]                  .... (i) \[{{H}^{+}}(aq)+O{{H}^{-}}(aq)\xrightarrow{{}}{{H}_{2}}O(l);\] \[\Delta H=-57.3kJ\]                 .... (ii) \[\frac{1}{2}{{H}_{2}}(g)+aq\xrightarrow{{}}{{H}^{+}}{{(aq)}^{+}}{{e}^{-}};\Delta H=0\] (by convention)                    .... (iii) (ii) - (iii) gives, \[\frac{1}{2}{{H}_{2}}\left( g \right)+\frac{1}{2}{{O}_{2}}\left( g \right)+{{e}^{-}}+aq\xrightarrow{{}}O{{H}^{-}}\left( aq \right)\] \[\Delta H=-285.8+57.3=-228.5kJ\]


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