A) 13.7 kcal of heat is evolved with the formation of 87 g of \[{{K}_{2}}S{{O}_{4}}\], leaving no KOH.
B) 27.4 kcal of heat is evolved with the formation of 87 g of \[{{K}_{2}}S{{O}_{4}}\], leaving 4 gram equivalent of KOH.
C) 15.7 kcal of heat is evolved with the formation of 1 gram equivalent of\[{{K}_{2}}S{{O}_{4}}\], leaving 56 g of KOH.
D) 13.7 kcal of heat is evolved with the formation of 87g of \[{{K}_{2}}S{{O}_{4}}\], leaving 1 gram equivalent of KOH.
Correct Answer: D
Solution :
[d] \[\underset{49}{\mathop{\underset{98}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,}}\,+\underset{56}{\mathop{\underset{112}{\mathop{2KOH}}\,}}\,\to \underset{87}{\mathop{\underset{174}{\mathop{{{K}_{2}}S{{O}_{4}}}}\,}}\,+\underset{1\,mole}{\mathop{\underset{2\,mole}{\mathop{2{{H}_{2}}O}}\,}}\,\] 13.7 kcal is the heat evolved when 1 gev of strong acid is neutralised by 1 gev of strong base.
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