\[{{S}_{2}}\left( s \right)+2{{O}_{2}}\left( g \right)\xrightarrow{{}}2S{{O}_{2}}\left( g \right);\Delta G=-544kJ\] |
\[2Zn\left( s \right)+{{S}_{2}}\left( s \right)\xrightarrow{{}}2ZnS\left( s \right);\Delta G=-293\text{ }kJ\] |
\[2Zn\left( s \right)+{{O}_{2}}\left( g \right)\xrightarrow{{}}2ZnO\left( s \right)\text{ };\Delta G=-480kJ\] |
Then \[\Delta G\] for the reaction: |
\[2ZnS(s)+3{{O}_{2}}(g)\xrightarrow{{}}2ZnO(s)+2S{{O}_{2}}(g)\]will be: |
A) \[-357\text{ }kJ\]
B) \[-731kJ\]
C) \[-773\text{ }kJ\]
D) \[-229\text{ }kJ\]
Correct Answer: B
Solution :
[b] For the reaction \[2\,ZnS\to 2\,Zn+{{S}_{2}}:\Delta {{G}_{1}}^{{}^\circ }=293kJ\] .........(i) \[2\,Zn+{{O}_{2}}\to 2\,ZnO;\Delta {{G}_{2}}^{{}^\circ }=-480kJ\]..........(ii) \[{{S}_{2}}+2{{O}_{2}}\to 2S{{O}_{2}};\Delta G{{ }_{3}}^{{}^\circ }=-544kJ\].........(iii) \[\Delta {{G}^{{}^\circ }}\] for the reaction \[2ZnS+3{{O}_{2}}\to 2ZnO+2S{{O}_{2}}\] can be obtained by adding eqn. (i), (ii) and (iii) \[\Rightarrow \,\,\Delta G{}^\circ =293-480-544=-731\text{ }kJ\]You need to login to perform this action.
You will be redirected in
3 sec