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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    The enthalpies of formation of \[A{{l}_{2}}{{O}_{3}}\] and \[C{{r}_{2}}{{O}_{3}}\]are\[-1596\text{ }kJ\] and \[-1134\text{ }kJ\] respectively. \[\Delta H\]for the reaction \[2Al+C{{r}_{2}}{{O}_{3}}\to 2Cr+A{{l}_{2}}{{O}_{3}}\] is

    A) \[-2730\text{ }kJ\]         

    B) \[-462\,kJ\]

    C) \[-1365\,kJ\]                  

    D) \[+2730\,kJ\]

    Correct Answer: B

    Solution :

    [b] \[2Al+\frac{3}{2}{{O}_{2}}\to A{{l}_{2}}{{O}_{3}},\text{ }\Delta H=-1596kJ\].....(i) \[2Cr+\frac{3}{2}{{O}_{2}}\to C{{r}_{2}}{{O}_{3}},\,\Delta H=-~1134kJ\]    .......(ii) By (i)-(ii) \[2Al+C{{r}_{2}}{{O}_{3}}\to 2Cr+A{{l}_{2}}{{O}_{3}},\text{ }\Delta H=-462\text{ }kJ.\]


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