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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    The entropy of a sample of a certain substance increases by \[0.836\text{ }J\text{ }{{K}^{-1}}\] on adding reversibly 0.3344 J of heat at constant temperature. The temperature of the sample is:

    A) \[2.5\text{ }K\]              

    B) \[0.3\text{ }K\]

    C) \[0.016\text{ }K\]          

    D) \[~0.4\text{ }K\]

    Correct Answer: D

    Solution :

    [d] \[\Delta S=\frac{\Delta H}{T};\text{ T}=\frac{\Delta H}{\Delta S}=\frac{0.3344}{0.836}=0.4K\]


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