NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    A certain reaction is non spontaneous at 298K. The entropy change during the reaction is\[121\text{ }J{{K}^{-1}}\]. Is the reaction is endothermic or exothermic? The minimum value of \[\Delta H\] for the reaction is

    A) endothermic, \[\Delta H=36.06\text{ }kJ\]

    B) exothermic, \[\Delta H=-36.06\text{ }kJ\]

    C) endothermic, \[\Delta H=60.12\text{ }kJ\]

    D) exothermic, \[\Delta H=-60.12\text{ }kJ\]

    Correct Answer: A

    Solution :

    [a] For non spontaneous reaction \[\Delta G=+ve\] \[\Delta G=\Delta H-T\Delta S\] and \[\Delta S=121\text{ }J{{K}^{-1}}\] For \[\Delta G=+ve\] \[\Delta H\] has to be positive. Hence the reaction is endothermic. The minimum value of \[\Delta H\] can be obtained by putting \[\Delta G=0\] \[\Delta H=T\Delta S=298\times 121\text{ }J\] \[=36.06\text{ }kJ\]


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