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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    What is the free energy change for the conversion of 1 mole of water into steam at \[373.2\text{ }K\]. The heat of vaporization \[\left( \Delta \,{{H}_{v}} \right)\] of water of \[373.2\text{ }K\] is \[9.1\text{ }kcal\text{ }mo{{l}^{-1}}\]. The entropy change is 25.5 cal/mol deg.         

    A) \[-401.6\text{ }cal/mol\]  

    B) \[-416.6\text{ }cal/mol\]

    C) \[516.5\text{ }cal/mol\]              

    D) \[-516.5\text{ }cal/mol\]

    Correct Answer: B

    Solution :

    [b] \[\Delta G=\Delta H-T\Delta S\] \[\therefore \Delta G=9100-373.2\times 25.5=-416.6cal\text{ }mo{{l}^{-1}}\]


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