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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    In a thermodynamic process, pressure of a fixed mass of gas is changed in such a manner that the gas molecules gives out 30 joules of heat and 10 J of work is done on the gas. If the initial internal energy of the gas was 40 J, then final internal energy will be

    A) zero      

    B)        80 J 

    C) 20 J                 

    D) -20 J

    Correct Answer: C

    Solution :

    [c] Given that \[dQ=-30\text{ }J\]and\[~dW=-10J\] \[{{E}_{i}}=40\text{ }J\] and let final internal energy\[={{E}_{f}}\] So, \[dQ={{E}_{f}}-{{E}_{i}}+dW\] \[-30=\text{ }{{E}_{f}}-40-10\] \[{{E}_{f}}=20J\]


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