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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    What is \[\Delta {{n}_{gas}}\] for the combustion of 1 mole of benzene, when both the reactants and the products are at 298 K ?

    A) 0                                 

    B) 1/2  

    C) 3/2                               

    D) \[-3/2\]

    Correct Answer: D

    Solution :

    [d] \[{{C}_{6}}{{H}_{6}}(l)+\frac{15}{2}{{O}_{2}}(g)\to 6C{{O}_{2}}(g)+3{{H}_{2}}O(l)\]             \[\therefore \Delta n=6-15/2=-3/2\]


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