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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    The enthalpy of the reaction forming \[PbO\] according to the following equation is \[438\text{ }kJ\]. What heat energy (kJ) is released in formation of \[22.3g\,PbO\left( s \right)\] ? (Atomic masses: \[Pb=207,\text{ O}=16.0\]) \[2Pb\left( s \right)+{{O}_{2}}\left( g \right)\xrightarrow{{}}2PbO\left( s \right)\]

    A) 21.9                 

    B) 28.7

    C) 14.6                             

    D) 34.2

    Correct Answer: A

    Solution :

    [a] \[Q=\frac{1}{2}438\times \frac{22.3}{223}=21.9\,KJ\]


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