JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    The pressure inside a tyre is 4 times that of atmosphere. If the tyre bursts suddenly at temperature 300 K, what will be the new temperature?

    A) \[300\text{ }{{\left( 4 \right)}^{772}}\]

    B) \[300\text{ }{{\left( 4 \right)}^{2/7}}\]

    C) \[300\text{ }{{\left( 2 \right)}^{772}}\]

    D) \[300{{\left( 4 \right)}^{-2/7}}\]

    Correct Answer: D

    Solution :

    [d] Under adiabatic change \[\frac{{{T}_{1}}}{{{T}_{2}}}{{\left( \frac{{{P}_{1}}}{{{P}_{2}}} \right)}^{\frac{1-\gamma }{\gamma }}}\,\,\,\,\,\,\,\,\text{or}\,\,\,\,\,\,\,\,\,\text{ }{{T}_{2}}={{T}_{1}}{{\left( {{P}_{1}}/{{P}_{2}} \right)}^{\frac{1-\gamma }{\gamma }}}\] \[\therefore {{T}_{2}}=300{{(4/1)}^{\frac{1-\left( 7/5 \right)}{\left( 7/5 \right)}}};\] \[\gamma =1.4=7/5\text{ for air}\] \[\text{or }{{T}_{2}}=300{{\left( 4 \right)}^{-2/7}}\]


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