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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    \[36mL\] of pure water takes 100 sec to evaporate from a vessel and heater connected to an electric source which delivers 806 watt. The\[\Delta {{H}_{vap}}\]of \[{{H}_{2}}O\] is:

    A) \[40.3\text{ }kJ/mol\]                 

    B) \[43.2\text{ }kJ/mol\]

    C) \[4.03\text{ }kJ/mol\]                 

    D) None of these

    Correct Answer: A

    Solution :

    [a] 1 watt = 1 J/sec Total heat supplied for \[36mL\,{{H}_{2}}O\] \[=806\times 100\] \[=80600\text{ }J\] \[\Delta {{H}_{vap}}=\frac{80600}{36}\times 18\] \[=40300\text{ }J\text{ }or\text{ }40.3\text{ }kJ/mol\]


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