A) \[W>0;{{P}_{3}}>{{P}_{1}}\]
B) \[W<0;{{P}_{3}}>{{P}_{1}}\]
C) \[W>0;{{P}_{3}}<{{P}_{1}}\]
D) \[W<0;{{P}_{3}}<{{P}_{1}}\]
Correct Answer: B
Solution :
[b] In the first process W is +ve as \[\Delta V\] is \[{{P}_{3}}\]positive, in the P1 second process W is \[{{P}_{2}}\] -ve as \[\Delta V\]is \[ve\] and area under the curve of second process is more \[\therefore \] Net Work \[<0\]and also\[{{P}_{3}}>{{P}_{1}}.\]You need to login to perform this action.
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