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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    The difference between the reaction enthalpy change \[({{\Delta }_{r}}H)\] and reaction internal energy change \[({{\Delta }_{r}}U)\] for the reaction: \[2{{C}_{6}}{{H}_{6}}\left( l \right)+15{{O}_{2}}\left( g \right)\xrightarrow{{}}12C{{O}_{2}}\left( g \right)+6{{H}_{2}}O\left( l \right)\]at \[300K\] is \[(R=8.314\,Jmo{{l}^{-1}}{{K}^{-1}})\]

    A) \[0J\,mo{{l}^{-1}}\]                

    B) \[2490\text{ }J\text{ }mo{{l}^{-1}}\]

    C) \[-2490J\text{ }mo{{l}^{-1}}\]             

    D) \[-7482J\text{ }mo{{l}^{-1}}\]

    Correct Answer: D

    Solution :

    [d] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\] For the reaction \[\Delta {{n}_{g}}=12-15=-3\] \[\Delta H-\Delta U=-3\times 8.314\times 300\] \[=-7482\text{ }J\text{ }mo{{l}^{-1}}\]


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