JEE Main & Advanced Physics Thermodynamical Processes Question Bank Self Evaluation Test - Thermodynamics

  • question_answer
    The internal energy change in a system that has absorbed 2 Kcal of heat and done 500 J of work is

    A) 8900 J

    B) 6400 J

    C) 5400 J

    D) 7900 J

    Correct Answer: D

    Solution :

    [d] \[\Delta Q=\Delta U+\Delta W\Rightarrow 2\times {{10}^{3}}\times 4.2=\Delta U+500\] \[\Rightarrow \Delta U=7900J\]


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