JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    A 5.9 g bullet (specific heat of material of bullet =\[128 J/kg{}^\circ C\]) moving with a velocity of 299 m/s enters a sand bag and stops. If the entire kinetic energy of the bullet is changed into heat energy that is added to the bullet, then the rise in the temperature of the bullet is   

    A) \[312.5{}^\circ C\]                   

    B) \[156{}^\circ C\]

    C) \[500{}^\circ C\]          

    D)        \[624{}^\circ C\]

    Correct Answer: B

    Solution :

    [b] \[\frac{1}{2}m{{v}^{2}}=mC\Delta T\]  \[\therefore \Delta T=\frac{{{v}^{2}}}{2C}=\frac{{{200}^{2}}}{2\times 128}=156{}^\circ C\]


You need to login to perform this action.
You will be redirected in 3 sec spinner