JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    A container contains hot water at \[100{}^\circ C\]. If in time \[{{T}_{1}}\] temperature falls to \[80{}^\circ C\] and the time \[{{T}_{2}}\] temperature falls to \[60{}^\circ C\] form \[80{}^\circ C\], then

    A) \[{{T}_{1}}={{T}_{2}}\]         

    B)        \[{{T}_{1}}>{{T}_{2}}\]

    C) \[{{T}_{1}}<{{T}_{2}}\]         

    D)        None of these

    Correct Answer: C

    Solution :

    [c] Rate of coiling\[=\frac{-d\theta }{dt}\propto \left( \frac{{{\theta }_{1}}+{{\theta }_{2}}}{2}-{{\theta }_{0}} \right)\] In second case average temperature will be less hence rate of coiling will be less. Therefore time taken will be more than 4 minutes.


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