A) 3 kW
B) 4 kW
C) 5 kW
D) 6 kW
Correct Answer: D
Solution :
[d] Rate of heat loss with only room heater \[\operatorname{Ph}=\frac{\Delta Q}{\Delta t}=C\left( 16+20 \right), C= constant\] while for both heater and stove it is \[{{p}_{h}}+{{p}_{s}}={{\left( \frac{\Delta Q}{\Delta t} \right)}^{'}}=C\left( 22+20 \right)\] \[\frac{{{p}_{h}}}{{{p}_{h}}+{{p}_{s}}}=\frac{36}{42}\Rightarrow 7{{p}_{h}}=6{{p}_{h}}+6{{p}_{s}}\] \[\Rightarrow {{p}_{h}}=6{{p}_{s}}=6kW\]
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