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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    Assuming no heat losses, the heat released by the condensation of x g of steam at \[100{}^\circ C\] can be used to convert y g of ice at \[0{}^\circ C\] into water at\[100{}^\circ C\], the ratio x:y is:

    A) 1 : 1 

    B) 1 : 2 

    C) 1 : 3 

    D) 3 : 1

    Correct Answer: C

    Solution :

    [c] The heat lost in condensation\[=x\,\times 540 cal\]. \[\therefore  x\,\times 540=y\times 80+y\times l\times  \left( 100-0 \right)\] or \[\frac{x}{y}=\frac{1.}{3}\].


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