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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    12 identical rods made of same material are arranged in the form of a cube. The temperature of P and R are maintained at \[90{}^\circ C\] and \[30{}^\circ C\]respectively. Then the temperature of point V, when steady state is reached is

    A) \[65{}^\circ C\]

    B) \[60{}^\circ C\]

    C) \[20{}^\circ C\]

    D) \[50{}^\circ C\]

    Correct Answer: D

    Solution :

    [d] \[\frac{90-V}{2{{R}_{T}}}=\frac{V-30}{{{R}_{T}}}\Rightarrow V={{50}^{\operatorname{o}}}C\]


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