A) \[\frac{3}{8}\operatorname{E}\]
B) \[\frac{81}{16}\operatorname{E}\]
C) \[\frac{9}{16}\operatorname{E}\]
D) \[\frac{81}{64}\operatorname{E}\]
Correct Answer: D
Solution :
[d] \[\operatorname{E}=\sigma \times area\times {{T}^{4}}\]; T increases by a factor \[\frac{3}{2}\]. Area increases by a factor\[\frac{1}{4}\]. \[\Rightarrow E'\frac{1}{4}\times {{\left( \frac{3}{2} \right)}^{4}}\times E=\frac{81}{64}E\]
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