A) 100
B) 200
C) 300
D) 400
Correct Answer: C
Solution :
[c] Specific heat of water = 4200 J/kg-K Latent heat of fusion \[=3.36\times 1{{0}^{5}} J/kg\] Latent heat of vapourisation \[=22.68\times l{{0}^{5}} J/kg\] \[\operatorname{x}\times 1{{0}^{-3}}\times 22.68\times {{10}^{5}}J\] \[=y\times 1{{0}^{-3}}\times 3.36\times 1{{0}^{5}} J+y\times 1{{0}^{-3}}\times 4200\times 100\]\[\therefore \frac{x}{y}=\frac{7.56}{22.68}=\frac{1}{3}\]
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