A) \[7.1{}^\circ C\]
B) \[9.2{}^\circ C\]
C) \[10.5{}^\circ C\]
D) \[12.1{}^\circ C\]
Correct Answer: A
Solution :
[a] \[\operatorname{W}=JQ\Rightarrow \frac{1}{2}\left( \frac{1}{2}M{{v}^{2}} \right)=J\left( m.c.\Delta \theta \right)\] \[\frac{1}{4}\times 1\times {{\left( 50 \right)}^{2}}= 4.2\left[ 200\times 0.105\times \Delta \theta \right]\] \[\Rightarrow \Delta \theta =7.1{}^\circ C\]
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