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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    500 g of water and 100 g of ice at \[0{}^\circ C\]are in a calorimeter whose water equivalent is 40 g. 10 g of steam at \[100{}^\circ C\] is added to it. Then water in the calorimeter is : (Latent heat of ice =80 cal/g, Latent heat of steam =540 cal/ g)

    A) 580 g

    B) 590 g

    C) 600 g

    D) 610 g

    Correct Answer: B

    Solution :

    [b] As Ig of steam at \[100{}^\circ C\] melts 8g of ice at 10 g of steam will melt \[8\times 10g\] of ice at \[0{}^\circ C\] Water in calorimeter =500 + 80+10g=590g


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