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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    A lead bullet strikes against a steel plate with a velocity \[200 m {{s}^{-1}}\]. If the impact is perfectly inelastic and the heat produced is equally shared between the bullet and the target, then the rise in temperature of the bullet is (specific heat capacity of lead \[=125J\,k{{g}^{-l}}{{K}^{-l}}\])

    A) \[80{}^\circ C\]

    B) \[60{}^\circ C\]

    C) \[160{}^\circ C\]

    D) \[40{}^\circ C\]

    Correct Answer: A

    Solution :

    [a] Heat produced \[=ms\Delta T =\frac{1}{2}\left( \frac{1}{2}m{{v}^{2}} \right)\] \[\Rightarrow \Delta T=\frac{{{v}^{2}}}{4s}=\frac{{{(200)}^{2}}}{4\times 125}=\frac{4\times {{10}^{4}}}{4\times 125}={{80}^{\operatorname{o}}}C\]


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