A) \[37.2{}^\circ C\]
B) \[33.3{}^\circ C\]
C) \[55.4{}^\circ C\]
D) \[40.2{}^\circ C\]
Correct Answer: B
Solution :
[b] \[\rho =\frac{{{\rho }_{0}}}{1+\gamma \,\Delta \theta }\cong {{\rho }_{0}}\left( 1-\gamma \,\Delta \theta \right);\frac{\Delta \rho }{\rho }=-\gamma \,\Delta \theta \] \[\frac{1}{100}=3\times {{10}^{-5}}\Delta \theta \,\,\,\,;\,\,\,\Delta \theta =\frac{100}{3}={{33.3}^{\operatorname{o}}}C\]
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