JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    Six identical conducting rods are joined as shown in figure. Points A and D are maintained at \[200{}^\circ C\]and \[20{}^\circ C\]respectively. The temperature of junction B will be

    A) \[120{}^\circ C\]

    B) \[100{}^\circ C\]

    C) \[140{}^\circ C\]

    D) \[80{}^\circ C\]

    Correct Answer: C

    Solution :

    [c] Temperature difference between the end point A and \[\operatorname{D} =200-20 =180{}^\circ C\] As the resistance for the three parts are equal, the temperature difference must be distributed equally in the three part \[(=180/3=60{}^\circ C)\] \[\therefore \] Temperature of \[\operatorname{B}=200{}^\circ C-60{}^\circ = 140{}^\circ C\]


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