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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    A steel rod of length 1 m is heated from \[25{}^\circ C\] to \[75{}^\circ C\] keeping its length constant. The longitudinal strain developed in the rod is (Given: Coefficient of linear expansion of steel \[=12\times {{10}^{-6}}/{}^\circ C\])

    A) \[6\times {{10}^{-6}}\]

    B) \[-6\times {{10}^{-5}}\]

    C) \[-6\times {{10}^{-4}}\]

    D) zero

    Correct Answer: B

    Solution :

    [c] Strain developed \[\varepsilon =\alpha \,\Delta T=(12\times 1{{0}^{-6}})(50)=6\times 1{{0}^{-4}}\] Strain will be negative, as the rod is in a compressed state.


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