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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    A pendulum clock is 5 seconds fast at temperature of \[15{}^\circ C\]and 10 seconds slow at a temperature of\[30{}^\circ C\]. At what temperature does it give the correct time? (take time interval = 24 hours)

    A) \[18{}^\circ C\]

    B)        \[20{}^\circ C\]

    C) \[22{}^\circ C\]            

    D)        \[25{}^\circ C\]

    Correct Answer: C

    Solution :

    [c] \[\Delta t=\frac{1}{2}\alpha \Delta T\times t\] \[\therefore  5=\frac{1}{2}\alpha \left( T-15 \right)\times 86400\] and \[10=\frac{1}{2}\alpha \left( 30-T \right)\times 86400\]


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