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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    One end of a uniform rod of length 1 m is placed in boiling water while its other end is placed in melting ice. A point P on the rod is maintained at a constant temperature of \[800{}^\circ C\]. The mass of steam produced per second is equal to the mass of ice melted per second. If specific latent heat of steam is 7 times the specific latent heat of ice, the distance of P from the steam chamber must be

    A) (1/7) m

    B)        (1/8) m 

    C) (1/9) m

    D)        (1/10) m  

    Correct Answer: C

    Solution :

    [c] \[{{Q}_{1}}=kA\left( \frac{800-100}{x} \right)t=m{{L}_{stream}}\] \[{{Q}_{2}}=kA\left( \frac{800-100}{1-x} \right)t=m{{L}_{ice}}\] Dividing \[\left( \frac{700}{x} \right)\left( \frac{1-x}{800} \right)=7\] or \[1-x=8x\,\,or\,\,x=\frac{1}{9}m\]


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