A) 1002.4
B) 1004.2
C) 1006.4
D) 1008.2
Correct Answer: A
Solution :
[a] \[{{T}_{1}}= 0{}^\circ C, {{T}_{2}}= 100{}^\circ C\] \[\gamma =\frac{{{V}_{2}}-{{V}_{1}}}{100{{V}_{1}}};\alpha =\frac{{{\ell }_{2}}-{{\ell }_{1}}}{100{{\ell }_{1}}}\] \[{{\ell }_{1}}=10\operatorname{cm};{{\ell }_{2}}-{{\ell }_{1}}=0.08mm=0.008\operatorname{cm}\] \[\alpha =\frac{0.008}{10\times 100}=8\times {{10}^{-6}}{{/}^{\operatorname{o}}}\operatorname{C}\] \[\gamma =3\alpha =24\times {{10}^{-6}}{{/}^{\operatorname{o}}}C\] \[\therefore 24\times {{10}^{-6}}=\frac{{{V}_{2}}-1000}{1000\times 100}\] \[{{V}_{2}}-1000\times 24\times {{10}^{-6}}\times {{10}^{5}}=2.4\] \[\therefore {{V}_{2}}=1002.4\operatorname{cc}\]
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