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JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Question Bank Self Evaluation Test - Thermal Properties of Matter

  • question_answer
    A glass flask is filled up to a mark with 50 cc of mercury at \[18{}^\circ C\]. If the flask and contents are heated to \[38{}^\circ C\], how much mercury will be above the mark? (\[\alpha \] for glass is \[9\times {{10}^{-6}}/{}^\circ C\] and coefficient of real expansion of mercury is \[80\times {{10}^{-6}}/{}^\circ C\])

    A) 0.85 cc

    B) 0.46 cc

    C) 0.153cc

    D) 0.05 cc

    Correct Answer: C

    Solution :

    [c] Due to volume expansion of both mercury and flask, the change in volume of mercury related to flask is given by \[\Delta V={{V}_{0}}\left[ {{\gamma }_{L}}-{{\gamma }_{g}} \right]\Delta \theta =V\left[ {{\gamma }_{L}}-3{{\alpha }_{g}} \right]\Delta \theta \] \[=50\left( 180\times {{10}^{-6}}-3\times 9\times {{10}^{-6}} \right]\left( 38-18 \right)\] \[=\,0.153\,cc\]


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