A) \[99{}^\circ C\]
B) \[59{}^\circ C\]
C) \[19{}^\circ C\]
D) \[67{}^\circ C\]
Correct Answer: A
Solution :
[a] From formula temperature of junction; \[\theta =\frac{{{k}_{copper}}{{\theta }_{copper}}{{l}_{steel}}\text{+}{{\text{K}}_{steel}}{{\theta }_{steel}}{{l}_{copper}}}{{{K}_{copper}}{{l}_{steel}}+{{k}_{steel}}{{l}_{copper}}}\] \[=\frac{9k\times 100\times \frac{L}{2}+k\times 0\times \frac{L}{2}}{9k\times \frac{L}{2}+k\times \frac{L}{2}}=\frac{\frac{900}{2}kL}{\frac{10kL}{2}}={{90}^{\operatorname{o}}}C\]
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