A) \[30g \text{ }mo{{l}^{-1}}\]
B) \[27g mo{{l}^{-1}}\]
C) \[20g mo{{l}^{-1}}\]
D) \[40g mo{{l}^{-1}}\]
Correct Answer: B
Solution :
[b] Density is given by \[d=\frac{Z\times M}{{{N}_{A}}{{a}^{3}}};\] where Z = number of formula units present in unit cell, which is 4 for fcc a = edge length of unit cell. M= Molecular mass \[2.72=\frac{4\times M}{6.02\times {{10}^{23}}\times {{\left( 404\times {{10}^{-10}} \right)}^{3}}}\] \[(\therefore 1 pm={{10}^{-10}}cm)\] \[M=\frac{2.72\times 6.02\times {{(404)}^{3}}}{4\times {{10}^{7}}}\] \[=26.99=27\text{ }gm\,mol{{e}^{-1}}\]
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