NEET Chemistry The Solid State / ठोस प्रावस्था Question Bank Self Evaluation Test - The Solid State

  • question_answer
    The number of atoms in 100 g of an fcc crystal with density, \[d=10g/c{{m}^{3}}\] and cell edge equal to 100 pm, is equal to

    A) \[1\times {{10}^{25}}\]    

    B) \[2\times {{10}^{25}}\]

    C) \[3\times {{10}^{25}}\]    

    D) \[4\times {{10}^{25}}\]

    Correct Answer: D

    Solution :

    [d]  \[M=\frac{\rho \times {{a}^{3}}\times {{N}_{A}}\times {{10}^{-30}}}{4}\] \[=\frac{10\times {{(100)}^{3}}\times 6.02\times {{10}^{23}}\times {{10}^{-30}}}{4}=15.05\] \[\therefore \] Number of atoms in 100 g \[=\frac{6.02\times {{10}^{23}}}{15.05}\times 100=4\times {{10}^{25}}\]


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