A) \[KCl\]
B) \[NaCl\]
C) \[Ca{{F}_{2}}\]
D) \[MgC{{l}_{2}}\]
Correct Answer: C
Solution :
[c] Among the three options\[KCl\], \[NaCl\] and \[MgC{{l}_{2}}\], the size of anion is same. So larger the cation, larger will be the cation/anion ratio i.e., \[KCl\] will have larger cation/anion ratio among the three. So, we left with two options \[KCl\] and \[Ca{{F}_{2}}\]. Among these two \[Ca{{F}_{2}}\] will have maximum value of cation/ anion ratio because decrease in ionic radii of anion from \[C{{l}^{-}}\] to \[{{F}^{-}}\] does not overcome the effect of decrease in ionic radii of cation from \[{{K}^{+}}\] to \[C{{a}^{2+}}\].
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