A) \[0.575\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[1.00\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[2.00\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[1.15\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: D
Solution :
[d] Order of Bragg diffraction (n) = 2: Wavelength \[\left( \lambda \text{ }\!\!~\!\!\text{ } \right)=1\,\overset{\text{o}}{\mathop{\text{A}}}\,\] and angle\[\left( \theta \right)=60{}^\circ \]. We know from the Bragg's equation \[n\lambda =2d\sin \theta \] Or \[2\times 1=2dsin\,{{60}^{{}^\circ }}\] \[\Rightarrow 2\times 1=2.d\frac{\sqrt{3}}{2}\Rightarrow d=\frac{2}{\sqrt{3}}=1.15\overset{\text{o}}{\mathop{\text{A}}}\,\] (where d = Distance between the scattering planes)
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