A) \[10.9\times {{10}^{-36}}{{m}^{3}}\]
B) \[10.9\times {{10}^{-30}}{{m}^{3}}\]
C) \[21.8\times {{10}^{-30}}{{m}^{3}}\]
D) \[21.8\times {{10}^{-36}}{{m}^{3}}\]
Correct Answer: B
Solution :
[b] For bcc lattice, \[\sqrt{3}a=4R\Rightarrow a=\frac{4\times 96}{\sqrt{3}}pm=221.7pm\] (where R is the radius of Ca atom) Colume of unit cell \[={{a}^{3}}={{(211.7\times {{10}^{-12}})}^{3}}{{m}^{3}}\] \[=10.9\times {{10}^{-30}}{{m}^{3}}\]
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