A) \[N{{a}_{2}}W{{O}_{3}}\]
B) \[N{{a}_{2}}W{{O}_{2}}\]
C) \[NaW{{O}_{2}}\]
D) \[NaW{{O}_{3}}\]
Correct Answer: D
Solution :
[d] In a unit cell, W atoms at the corner \[=\frac{1}{8}\times 8=1\] O-atoms at the centre of edges\[~=\frac{1}{4}\times 12=3\] Na-atoms at the centre of the cube = 1 \[W:O:Na=1:3:1\] Hence, formula \[=NaW{{O}_{3}}\]
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