A) \[CuAgAu\]
B) \[C{{u}_{4}}A{{g}_{4}}Au\]
C) \[C{{u}_{4}}A{{g}_{3}}Au\]
D) \[C{{u}_{4}}A{{g}_{6}}Au\]
Correct Answer: C
Solution :
[c] Number of Cu-atoms per unit cell \[=\frac{1}{8}\times 8+\frac{1}{2}\times 6=4.\] Number of Ag-atoms per unit cell \[=\frac{1}{4}\times 12=3\] Number of Au-atoms per unit cell = 1 (at body centre) Formula: \[C{{u}_{4}}A{{g}_{3}}Au\]
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