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NEET Chemistry The Solid State / ठोस प्रावस्था Question Bank Self Evaluation Test - The Solid State

  • question_answer
    The edge length of unit cell of a metal having molecular weight 75 g/mol is \[5\overset{{}^\circ }{\mathop{A}}\,\] which crystallizes in cubic lattice. If the density is 2g/cc then find the radius of metal atom.\[({{N}_{A}}=6\times {{10}^{23}})\]. Give the answer in pm.    

    A) 217pm     

    B) 210pm

    C) 220pm      

    D) 205pm 

    Correct Answer: A

    Solution :

    [a] \[\rho =\frac{ZM}{{{N}_{A}}V}\] \[Z=\frac{\rho {{N}_{A}}V}{M}=\frac{2\times 6\times {{10}^{23}}\times {{(5\times {{10}^{-8}})}^{3}}}{75}\] Z= 2, which represents bcc structure \[\therefore ~r=\frac{\sqrt{3}}{4}a=\frac{\sqrt{3}}{4}\times 5=2.165\overset{{}^\circ }{\mathop{A}}\,=216.5pm\] \[\approx 217pm\]


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