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NEET Chemistry The Solid State / ठोस प्रावस्था Question Bank Self Evaluation Test - The Solid State

  • question_answer
    In a face centred cubic lattice, atoms of A form the corner points and atoms of B form the face centred points. If two atoms of A are missing from the corner points, the formula of the ionic compound is:

    A) \[A{{B}_{3}}\]                         

    B) \[A{{B}_{4}}\]

    C) \[{{A}_{2}}{{B}_{5}}\]                       

    D) \[A{{B}_{2}}\]

    Correct Answer: B

    Solution :

    [b] A form corner points and two atoms of A are missing from corner \[\therefore \] Atoms at corner \[\left( A \right)=6\times \frac{1}{8}=\frac{3}{4}\] Atoms at face centre \[\left( B \right)=6\times \frac{1}{2}=3\] \[\therefore {{A}_{3/4}}{{B}_{3}}i.e.,A{{B}_{4}}\]


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