question_answer

A solid compound 'X' on heating gives \[C{{O}_{2}}\] gas and a residue. The residue mixed with water forms 'Y'. On passing an excess of \[C{{O}_{2}}\] through 'Y' water, a clear solution 'Z', is obtained. On boil. 'Z', compound 'X' is reformed. The compound 'X' is

A) \[Ca{{(HC{{O}_{3}})}_{2}}\]              

B) \[CaC{{O}_{3}}\]

C) \[N{{a}_{2}}C{{O}_{3}}\]      

D) \[{{K}_{2}}C{{O}_{3}}\]

Correct Answer: B

Solution :

[b]   The given properties coincide with \[CaC{{O}_{3}}\]